Question

11.
A car on the cross road is moving towards east at
a speed of 40 km/hr. Another car which is 1 km
south of the crossing is approaching the crossing
with the same speed. Their closest distance of
approach will be​

Answer 1

Answer:

A car on the cross road is moving towards east at

a speed of 40 km/hr. Another car which is 1 km

south of the crossing is approaching the crossing

with the same speed. Their closest distance will be 1/√ 2km

Explanation:

tanθ=v1/v2

θ=tan^(−1)40/40  

    =tan^(−1)(1)  

     =45°

For closest distance:

Distance, d=xsinθ                    

                    = 1 sin45°                    

                     =1×1/√ 2                    

                     =1/√ 2km