Question

11.
A cell of e.mf E, (= 2 V) and internal resistance 1 22 is connected in parallel with
another cell of e.m.f. E, (= 1.5 V) and internal resistance 2 12. When the combination
is in parallel with a resistance of 42, find the current through each branch and also
the potential difference across the 4 22 resistance.​

Answer 1

Answer:

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Explanation:

Two cells of emfs 1.5 V and 2.0V internall resistance 1 Omega and 2 Omega are connected in parallel so as to send current in the same direction through an external resistance of 5 Omega . <br> (i) Draw the circuit diagram. (ii) Using Kirchhoff's rules, calculate. <br> (a) current through each branch of the circuit (b) potential difference across the 5 Omega resistance.