Question

11. A current of 10 A is maintained in a conductor of cross-section 10-4 m2. If the
number density of free electrons is 9 x 1028 m3, then the drift velocity of free
electrons is

Answer 1

Answer:

Explanation:

The relation between current and drift velocity

I.e1=V  

d

​  

.e.n.a

where I= current  

V  

d

​  

= current velocity  

e= electron

n= no. of electrons per unit volume

a= area of cross section

Now, V  

d

​  

=  

nea

I

​  

 

              =  

1×10  

−4

×9×10  

7

×28

10

​  

=1.94×10  

−3

m/s