Question

11. A = i + 3j + 2k, B = 2i + bj + 3k then the value
of b It A perpendicular to B will be :
b)
d)​

Answer 1

Answer:

A×B=0

(i+3j+2k)×(2i+bj+3k)=0

2+3b+6=0

8+3b=0

3b= -8

b= -8/3