Math, asked by adarshkumar5960, 2 months ago

11. A man bought 60 oranges at the rate of 20 for 6 and sold them at 15 for 4. Find his total gain or loss.

Answers

Answered by himanshujc7
0

Answer:

He buys some oranges , say x oranges , at 20 for 60 Rs

20oranges=60Rs

1orange=60/20Rs=3Rs

xoranges=3xRs

Then he buys equal no. Of oranges = x , at 30 for 60 Rs

30oranges=60Rs

1orange=60/30Rs=2Rs

xoranges=2xRs

Total Cost Price = 3x + 2x = 5x Rs

He mixes two types of oranges and sells them at 25 for 60 Rs

25oranges=60Rs

1orange=(12/5)Rs

He had x+ x = 2x oranges to sell.

2xoranges=2x×(12/5)R=(24x/5)Ruppees

Selling price = ( 24x/5 ) Rs

C.P - S.P = 5x - (24x/5 )

Loss = x/5

Loss

=((x/5)÷5x)∗100

=(1/25)∗100=4

Answered by Anonymous
2

Step-by-step explanation:

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