Question

11. A number is divided into two parts such
that one part is 10 more than the other. If the
two parts are in the ratio 53, find the
number and the two parts.​

Answer 1

Answer:

Since the two parts are in the ratio 5:3, then let the first number be 5x and second number be 3x. As second number is 10 more than the other, so it will be 3x+10.

5x=3x+10

2x=10

x=5

The first number becomes 5(5)=25 and second number becomes 3(5)=15.

The new number will be 25+15=40.

Step-by-step explanation:

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Answer 2

Answer:-

The number is 40, and the two parts are 25 and 15

Step-by-step explanation:-

Correct question:-

A number is divided into two parts such  that one part is 10 more than the other. If the  two parts are in the ratio 5:3, find the  number and the two parts.​

Solution:-

Let the numbers be 5x and 3x

5x is 10 more than 3x

⇒ 5x = 3x + 10

⇒ 2x = 10

⇒ x = 5

The two parts = 5x and 3x

                       = 5(5) and 3(5)

                       = 25 and 15

The number = Sum of the two parts

                     = 25 + 15

                     = 40

Answer⇒ The number is 40, and the two parts are 25 and 15

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