Question

11. A pole of length 12 m casts a shadow of length 15.6 m.
(a) Find the length of the shadow cast by another pole of length 18 m.
(b) Find the height of the pole which casts a shadow of length 117 m.​

Answer 1

Answer:

hope this helps you.....

Step-by-step explanation:

We have,

Pole of height AB=10m

Shadow of length BC=12m

Same time

Pole of height AB=?

Shadow of length BC=15m

In ΔABC

tanθ=

BC

AB

=

12

10

…… (1)

InΔABC

tanθ=

BC

AB

=

15

AB

……. (2)

Angle is equal in same time,

By equation (1) and (2) to, we get

12

10

=

15

AB

AB=

12

10×15

AB=

4

10×5

AB=

2

25

=12.5m

Hence, this is the answer.