Question

11.
A train travelling along a straight track with a speed
of 2 ms-1, begins to accelerate with
a = 2/vms-2, where v is in ms- its velocity after
3 seconds is
(1) 1 ms-1
(2) 2 ms-1
(3) 3 ms-1
(4) 4 ms -1​

Answer 1

Answer:

8m/s

Explanation:

u=2m/s

t=3sec

a=2m/s-2

from equation first

v=u + at

v=2+6

v=8m/s-1