Question

11. An open cone has a circular base of radius 10 cm
and a slant height of 20 cm. Draw the net of the
cone and label its dimensions.​

Answer 1

Answer:

To draw the net of a cone first draw a straight line

and mark a point P(point of cone) use this as center

and draw a circle with radius S (slant height) The

sector of this circle you need is given by circumference

of base/ circumference of slant height circle,in this case

$angle = (20cm{\pi} )by40cm{\pi} = 360degrees = 180degrees$

so draw a half circle with radius 20cm (slant height)

and tangent to this half circle (touching edge to edge)

draw a complete circle with radius 10cm this is the base the larger half circle is the sides and the net is done

Explanation:

hope it helps you mark me as brilliant plzzzzzz.......

Answer 2

A open circular cone having base radius 10 cm and slant height 20 cm.

$\setlength{\unitlength}{30} \begin{picture}(20,10) \linethickness{1.2} \qbezier(1,1)(3., 0)(5,1)\qbezier(1,1)(3.,2)(5,1)\put(3,1){\circle*{0.15}}\put(3,1){\line(0,1){3}}\qbezier(1,1)(1,1)(3,4)\qbezier(5,1)(3,4)(3,4)\put(3,1){\line(1,0){2}}\put(3.2,1.1){ \sf 10 \: cm }\put(2.6,1.9){ \sf h }\put(4.6,2.1){ \sf 20 \: cm }\end{picture}$

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$\begin{gathered}{\frak{Here}}\begin{cases} & \text{h = Height } \\ & \text{r = 10 cm} \\ & \text{l = 20 cm} \end{cases}\end{gathered}$

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☯ Cone is a shape or object which have a round base and a point at the top.

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$\begin{gathered}\begin{gathered}\boxed{\bigstar{\sf \ Formula \: related \: to \: Cone :- }}\\ \\\sf {\textcircled{\footnotesize1}} Volume \ of \ Cone= \dfrac{1}{3}\pi r^2 h \\ \\ \\ \sf {\textcircled{\footnotesize2}}\ Curved \ surface\ Area \ of \ Cone = \pi r l \\ \\ \\ \sf {\textcircled{\footnotesize3}} Total \ surface \ Area \ of \ Cone = \pi r (l+r) \\ \\ \\ \sf {\textcircled{\footnotesize4}} Slant \ Height \ of \ cone (l)= \sqrt{r^2+h^2}\end{gathered}\end{gathered}$