Question

11. Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them?​

Answer 1

Answer:

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Answer 2

★ How to do :-

Here, we are given with that the age of a boy's father is 26 years less than the boy's grandfather and 29 years more than the boy. The name of boy is Baichung. We are also given with the sum of all the three members as 135. We can consider the age of Baichung's father as any variable, say x. Then, we can take his grandfather's age as 26 years more than x. The age of the boy may be 29 years less than x. Then, we can add all the equations and then, we can find the value of x by transposition method. So, let's solve!!

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➤ Solution :-

Let Baichung's father age be x years.

Let Baichung's grandfather age be x+26 years.

Let Baichung's age be x-29 years.

${\sf \leadsto x + (x + 26) + (x - 29) = 135}$

Add all the variables and constants on LHS.

${\tt \leadsto (x + x + x) + (26 - 29) = 135}$

Add the brackets in LHS.

${\tt \leadsto 3x - 3 = 135}$

Shift the number 3 from LHS to RHS.

${\tt \leadsto 3x = 135 + 3}$

Add the values on RHS.

${\tt \leadsto 3x = 138}$

Shift the number 3 from LHS to RHS, changing it's sign.

${\tt \leadsto x = \dfrac{138}{3}}$

Simplify the fraction to get the value of x.

${\tt \leadsto x = 46}$

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Now, let's find the age of each of them separately.

Baichung's grandfather age :-

${\tt \leadsto x + 26}$

Substitute the value of x.

${\tt \leadsto 46 + 26 = 72}$

Baichung's age :-

${\tt \leadsto x - 29}$

Substitute the value of x.

${\tt \leadsto 46 - 29 = 17}$

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$\begin{gathered} \small \boxed{\begin{array} {cc} \red{\bf Baichung's \: age = 17} \\ \\ \red{\bf Baichung's \: father \: age = 46} \\ \\ \red{\bf Baichung's\: grandfather \: age = 72} \end{array}} \end{gathered}$