11 boys be selected from 25 boys. How many ways 6 of them being always excluded and 5 of them being always included?
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2 ways for 1st case tht r....6/25 nd 6/11
nd for 2nd case 5/25 nd 5/11
nd for 2nd case 5/25 nd 5/11
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in two ways 6 of them being always excluded
6/25 and 6/11
in two ways 5 of them being always included
5/ 25 that is 1/5 and 5/11
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6/25 and 6/11
in two ways 5 of them being always included
5/ 25 that is 1/5 and 5/11
If this is right then mark my answer as Brainliest
and follow me... I'll try my best to help you.....
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