11) Calculate the atom economy of fermentation of sugar(glucose) to ethanol
C6H1206(aq)
2C2H5OH(aq) + 2CO2(g)
Answers
Explanation:
Atom economy is 51.1%
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Answer:
Atom economy = 51.1%
Explanation:
Atom economy is a measure of the efficiency of a chemical reaction in using the available reactants to produce the desired product.
It is expressed as a percentage and is calculated by dividing the molecular weight of the desired product by the sum of the molecular weights of all reactants.
In the fermentation of sugar (glucose) to ethanol, the balanced chemical equation is:
C6H12O6(aq) → 2C2H5OH(aq) + 2CO2(g)
The molecular weight of glucose is 180 g/mol, and the molecular weight of ethanol is 46 g/mol. Therefore, the atom economy can be calculated as:
Atom economy = (2 x 46 g/mol) / (180 g/mol) x 100%
Atom economy = 51.1%
This means that 51.1% of the atoms present in the reactant glucose are converted into the desired product ethanol. The remaining atoms are lost as carbon dioxide during the fermentation process.
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