Question

11. Calculate the number of aluminium ions present in 0.051 g of
aluminium oxide.
(Hint: The mass of an ion is the same as that of an atom of the
same element. Atomic mass of Al = 27 u)​

Answer 1

Answer:

no. of atoms = given mass/ molar mass

n = 0.051/ 68

( aluminum oxide = Al2 o3 = 68)

n =

Explanation:

plz calculate this value ..

hope it helps you ☝️.