Question

11. Find the area to be painted in the following block Fig. 11.57 with a cylindrical hole
Given that length is 15 cm, width 12 cm, height 20 cm and radius of the hole 2.8 cm.
12 cm

Please tell this question
I will mark the brainliest plzzzz.........​

Answer 1

Answer:

Surface area of remaining block = Surface area of cuboid + Curved surface area of cylinder - 2× area of base

=A

I

+A

II

A

II

=2π(3.5)5−2π(3.5)

2

= 33cm

2

A

I

=2(15×10+10×5+5×15)=2×275=550cm

2

A

total

=583cm

2