Question

11. Find the mean proportional between:
(i) 6 and 24
(ii) 3 and 27 (iii) 0.4 and 0.9
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Answer 1

Answer:

(i) 1 and 4

(i)1 and 9

(i)0.2and 0.3

Answer 2

Answer:

(I) let the no be a

6:a=a:24

a×a=6×24

a×a=144

a=12

(ii) let the no be c

3:c=c:27

3/c=c/27

c^2=27*3

c^2=81

c=√81

c=9

(III) let the no be d

0.4:d=d:0.9

0.4/d=d/0.9

d^2=0.4×0.9=0.36

d=√0.36

d=0.6

Step-by-step explanation:

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