Question

11. Find the sum of all natural number between 150 and 250 which are exactly
divisible by 5.
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Answer 1

Answer:

total number of numbers exactly divisible by 5 = (250-150) /5

=(100) /5

=20 numbers

therefore we know :-

d=5

a=150

N =20

Sn = n/2 (2a+(n-1) d)

= 20/2(2×150+(19) ×5)

= 10×(300+95)

=10×(395)

= 3950

ans :- 3940

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Answer 2

Answer:

4050

Step-by-step explanation:All number between 150 to 250 are natural

So add all the numbers with unit digit 0 and 5 between 150 and 250

therefore 155+160+165+170+175+180+185+190+195+200+205+210+215+220+225+230+235+240+245+250= 4050