Question

11. Find the time in which a sum of money gets doubled at the interest rate of 8% per annum.​

Answer 1

Answer:

ANSWER IS 12 YEARS AND 6 MONTHS

Step-by-step explanation:

SINCE , NEITHER AMOUNT NOR THE PRINCIPAL IS GIVEN , SO

LET THE PRINCIPAL BE "  P "

ACCORDING TO THE QUESTION , PRINCIPAL IS DOUBLED IN "T "YEARS ( T MEANS TIME ( SUPPOSED) )

SO, THE AMOUNT = 2 TIMES P ( DOUBLED THE P)

SO, AMOUNT = 2P

∵ AMOUNT IS GIVEN AS 2P AND PRINCIPAL IS GIVEN AS P

SO, SIMPLE INTEREST = AMOUNT - PRINCIPAL

= 2P - P = P

SO, SIMPLE INTEREST = P .

FORMULA FOR FINDING TIME IN SIMPLE INTEREST =

(SIMPLE INTEREST ×  100  ) ÷ ( PRINCIPAL × RATE PER ANNUM )

= P × 100  ÷  P × 8 % ( AS 8 IS THE RATE PER ANNUM AS GIVEN IN THE QUESTION )

SO NOW P ON BEING SEPERATED BY THE DIVISON SIGN ON BOTH THE SIDES , GETS CANCELLED AND 100/8 IS FINALLY REMAINING WHICH CAN BE SIMPLIFIED INTO 25/2 FRACTION FORM AND THIS FRACTION CAN BE AGAIN CONVERTED INTO A MIXED FRACTION OF 12 AND A HALF

∴ FINALLY ANSWER COMES AS 12 AND A HALF YEARS , HALF YEAR CAN ALSO BE SAID AS 6 MONTHS AS IN A YEAR THERE ARE 12 MONTHS WHOSE HALF IS 6 MONTHS .

SO ANSWER IS FINALLY 12 YEARS AND 6 MONTHS .

THANK YOU . FOR GIVING YOUR PRECIOUS TIME TO READ MY ANSWER . REGRETS AND SORRY FOR ANY MISTAKE I DID . AND ONCE AGAIN .

THANK YOU SO MUCH .  MAY SUCCESS TOUCH YOUR FEET