Question

11. Find the zero of the polynomial (x-2)2-(x+2)2​

Answer 1

Answer:

_8

Step-by-step explanation:

(x_2)2 _(x+2)2

simplify

(2x_4)_(2x+4)

And evaluate

2x_4_2x_4

2x and _2x gets cancelled

Finally; _4_4 is equal to _8

Answer 2

p(x)=(x-2)²-(x+2)²  

This is in the form of a²-b²  

p(x)=(x-2+x+2)(x-2-(x+2))  

p(x)=2x(x-2-x-2)  

p(x)=2x(-4)  

p(x)=-8x  

 

p(x)=0  

-8x=0  

x=0  

 

x=0 is the zero of the polynomial p(x)

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