Question

11. Find the zeros and verify the relation between the
zeros and the coefficients (i) x² + 7x + 10 (ii) x2 - 3
​

Answer 1

Answer:

⭐Here is ur answer ⭐

x²+7x+10

x²+5x+2x+10

x(x+5)+2(x+5)

(x+2)(x+5)

for zeros

x=-2 and x=-5

verifying them

$\alpha + \beta = \frac{ - b}{a} \\ - 2 + - 5 = - 7 \\ lhs = rhs \\ \alpha \beta = \frac{c}{a} \\ - 2( - 5) = 10 \\ lhs \: = rhs$

x²-3

$(x - \sqrt{3} )(x + \sqrt{3} ) \\ \\ \: \: \: \: for \: zero \\ x = \sqrt{3} x = \sqrt{ - 3} \\ verifying \\ \alpha + \beta = \frac{ - b}{a} \\ ( - \sqrt{3} ) + \sqrt{3} = 0 \\ lhs = rhs \\ \alpha \beta = \frac{c}{a} \\ ( - \sqrt{3} )( \sqrt{3} ) = - 3 \\ lhs = rhs$

Hope it helps you! ❤❤❤✔✔