Math, asked by madhuanushka2408, 4 months ago

11. Find whether or not the second polynomial is
factor of the first.
a) * - 4x + 4,x-2 (b) x2 – 5x + 84,x+
(C) 32 - 4x + 2 (d) 15x2 + x-6, 3x-2
(e) 2x3 + x²–5x+2, 2x+3
(1) 8x + 10x - 5x2 - 4x + 1, 232 + x-1.​

Answers

Answered by aditi12y
6

Answer:

11. Find whether or not the second polynomial is

factor of the first.

a) * - 4x + 4,x-2 (b) x2 – 5x + 84,x+

(C) 32 - 4x + 2 (d) 15x2 + x-6, 3x-2

(e) 2x3 + x²–5x+2, 2x+3

(1) 8x + 10x - 5x2 - 4x + 1, 232 + x-1.

Answered by walaraunte122
3

Answer:

(1) =  x =  - 2

Step-by-step explanation:

 - 4x + 4(x - 2) \\ x = (x - 2) \\ x  - 2

(2) = x2 - 5x + 84x +  \\ 3x + 84(x) \\ 3 {x}^{2}  + 84x \\  {x}^{3}  = 84

(3) = 32 - 4x + 2 \\ 34 = (4x) \\ 136x

(4)15x2 + x - 6 = 3x - 2 \\ 15x(2x - 6)(3x - 2) \\ 30 {x}^{2}  - 90x(3x - 2) \\ 60 {x}^{3} (3x - 2) \\ 180 {x}^{4}  - 120 {x}^{3}  \\ =  60x

(5)2x3 + 1 {x}^{2}  - 5x + 2 = 2x + 3 \\ 2x(3 {x}^{2}  - 5x + 2) (2x + 3) \\ 2x(3 {x}^{2}  - 7x)(5x) \\ 2x( - 4 {x}^{2} (5x) \\  - 8 {x}^{2}  = 5x \\ x = 8 + 5 \\ x = 13

(6)8x + 10x - 5x2 - 4x + 1 232 + x - 1 \\ 18x - (5x)8x + (1)232x(x - 1) \\ 90 {x}^{2}  - 8x(231x) \\ 82 {x}^{2}(231x) \\ 18942 {x}^{2}

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