11 g ram of a gas occupies 5.6 litres of volume at STP the gas is
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Molar gas volume at stp is :
1 mole = 22.4 litres
The moles of the gas is :
Moles = 5.6 / 22.4 = 0.25 moles
Moles = mass / molar mass
Molar mass = mass / moles
Molar mass = 11 / 0.25 = 44g/mol
The gas with a molar mass of 44g/mol is Carbon (iv) oxide.
This is given by :
CO₂
C = 12
O₂ = 16 × 2 = 32
12 + 32 = 44g/mol
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