Question

11 gram of a gas occupies 5.6 volume at STP the gas is

Answer 1

At STP = 1 mole of substanceoccupies 22.4L of volume. Therefore for the above gas to acquire 22.4 Lvolume its mass should be 22.4/5.6 x11 = 44g = molar mass of gas.

Answer 2

Given:

11 grams of gas occupies 5.6 volumes at STP.

To find:

We have to identify the gas.

Solution:

We know that at STP x grams of gas occupy 22.4 litres.

Where x is the molecular weight of the gas.

Hence we can write-

5.6 litres is occupied by 11 grams of gas.

So, 22.4 litres is occupied by 22.4×11/5.6=44 grams of gas.

Hence, the molecular weight of the gas is 44 grams.

Carbon Dioxide has a molecular weight of 44 grams.

So, the gas is carbon dioxide.