Question

11
How many digits are required to number the pages of a book having
256 pages ?​

Answer 1

90 pages from 10 to 99 will require 90*2=180 digits; 200-(90+9)=101 pages will require 101*3=303 digits. Total: 9+180+303=492.

9 pages from 1 to 9 will require 9 digits;

90 pages from 10 to 99 will require 90×2=180 digits;

200−(90+9)=101 pages will require 101×3=303 digits.

∴ The total number of digits required is 9+180+303=492.