Question

11. How many grams of concentrated nitric acid solution
should be used to prepare 250 mL of 2 M HNO,?
The concentrated acid is 70% (w/w) HNO3.
[NEET-2013]
(1) 90.0 g conc. HNO3 (2) 70.0 g conc. HNO3
(3) 54.0 g conc. HNO3 (4) 45.0 g conc. HNO3​

Answer 1

Answer:

option no.4

Explanation:

no. of moles = $\frac{250*1000}{2}$

=0.5

no. of moles = molerity * volume

required mass of $HNO_{3}$

=0.5*63

=31.5 gm

70 gm of $HNO_{3}$ are present in 100 gm of solution

so 1 gm will be present in $\frac{100}{70}$ gm of solution

31.5 gm be present in $(\frac{100}{70}*31.5 )gm$ of solution

=45%

god bless you in your neet

Answer 2

11. How many grams of concentrated nitric acid solution

should be used to prepare 250 mL of 2 M HNO,?

The concentrated acid is 70% (w/w) HNO3.

[NEET-2013]

(1) 90.0 g conc. HNO3 (2) 70.0 g conc. HNO3

(3) 54.0 g conc. HNO3 (4) 45.0 g conc. HNO3

Option D