11. If 3x – 2y = 11 and xy = 12, find the value of 27 x3 – 8y3
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Answer:
3x-3y=11.........1
xy=12
x=12/y.......2
substitute 1 and 2
36/y-3y=11
36-3y=11y
14y=36
y=18/7
x=14/3(substitute y with equation 2 to get x)
27(14/3)^3-8(18/7)^3
2607.97 is the answer(after simplification)
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