Math, asked by nairpreethesh342, 1 year ago

11.
If -4 is a root of the quadratic equation 2x2 + px - 2 = 0 , the
value of
p
is​

Answers

Answered by mahabir837
1

Step-by-step explanation:

hear are you with the correct

answer and you can check also by putting the value of p obtained in given equation .........

Attachments:
Answered by Anonymous
2

\huge{\underline{\mathfrak{\red{Answer}}}}

________________________

\large{\star{\gray{\sf{Given}}}}

-4 is a root of quadratic equation 2x² + px - 2 = 0

\rule{200}{2}

\large{\star{\gray{\sf{To \:  Find}}}}

We have to find the value of p

\rule{200}{2}

\large{\star{\gray{\sf{Solution}}}}

As, one root of the quadratic equation is given.

So, if we will put the value of x as -4. Then, we can get the value of p.

\sf{\implies 2(-4)^2 + p(-4) - 2 = 0} \\ \\ \sf{\implies 2(16) - 4p - 2 =0} \\ \\ \sf{\implies 32 -2 = 4p} \\ \\ \sf{\implies 4p = 30} \\ \\ \sf{\implies p = \frac{\cancel{30}}{\cancel{4}}} \\ \\ \sf{\implies p = \frac{15}{2}}

\large{\star{\boxed{\boxed{\orange{\sf{p = \frac{15}{2}}}}}}}

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