11. If the roots of k-3)x2 + 6x = -9 are real and eual then k=
A) 4
C)-1
B) 3
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Answer:
if roots are equal so b^2 - 4ac=0
6^2-4*k-3*9=0
36+108k=0
108k=-36
k=-36/108
k=-1/3
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