Question

11. If the roots of k-3)x2 + 6x = -9 are real and eual then k=
A) 4
C)-1
B) 3​

Answer 1

Answer:

if roots are equal so b^2 - 4ac=0

6^2-4*k-3*9=0

36+108k=0

108k=-36

k=-36/108

k=-1/3