Question

11. If the speed of a car is halved, how does its kinetic

energy change ? Ans. It becomes one-fourth​

Answer 1

Answer:

K.E=0.5m×v

2

If v becomes v/2 then,

K.E=0.5×m×(v/2)

2

K.E=0.5×m×v

2

/4

Hence K.E becomes one fourth times the original.

Answer 2

Answer:

Answer:

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