11. If the sum of the first 14 terms of an AP is 1050 and its first term is 10, find the 20th term.
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Hey dear, here is your answer goes...
Accor. to question
n=14
S14=1050
a=10
a20=?
S14=n/2(2a+(n-1)d)
1050=7(20+13d)
1050=140+91d
1050-140=91d
910=91d
d=10
a20=a+(n-1)d
a20=10+19*10
a20=10+190
a20=200
hope it helps u dear.....
Accor. to question
n=14
S14=1050
a=10
a20=?
S14=n/2(2a+(n-1)d)
1050=7(20+13d)
1050=140+91d
1050-140=91d
910=91d
d=10
a20=a+(n-1)d
a20=10+19*10
a20=10+190
a20=200
hope it helps u dear.....
Ananyajha:
dude it is wrong
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