Question

11. If x' = ex-y then​

Answer 1

Answer:

y = e^(x - 2)

Taking the natural logarithm of both sides yield:

ln(y) = ln[e^(x - 2)]

Through the rule ln(e^x) = x, we have:

ln(y) = x - 2

Adding 2 to both sides yield:

ln(y) + 2 = x

Our final answer is:

==> x = ln(y) + 2

I hope this helps!