Question

((11. In a cricket match, a batsman hits a boundary 6 times out of 30 balls
he plays. Find the probability that he did not hit a boundary.
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Answer 1

AnswEr :

$\bigstar\:\boxed{\sf Probability = \dfrac{Number\:of\: Outcomes}{Total\: Outcomes}}$

$\rule{150}{1}$

$\underline{\bigstar\:\textsf{According to the Question :}}$

$:\implies\tt Probability = \dfrac{Number\:of\: Outcomes}{Total\: Outcomes}\\\\\\:\implies\tt P(NB) = \dfrac{Not\:Hit\: Boundary}{Total\:Ball\:Played}\\\\\\:\implies\tt P(NB) = \dfrac{(Total-Hit\: Boundary)}{Total\:Ball\:Played}\\\\\\:\implies\tt P(NB) = \dfrac{(30-6)}{30}\\\\\\:\implies\tt P(NB) = \dfrac{24}{30}\\\\\\:\implies\tt P(NB) = \dfrac{4}{5}\\\\\\:\implies \boxed{ \red{\tt P(NB) = 0.8}}$

⠀

$\therefore\:\underline{\textsf{Probability of not hitting boundary is \textbf{0.8}}}$

Answer 2

Answer:

The probability that he did not hit a boundary is 0.8

Step-by-step explanation:

Probability that he did not hit a boundary = 1 - Probability that he hit the boundary

PROBABILITY THAT HE HIT THE BOUNDARY =

$6 \div 30$

Probability that he did not hit a boundary = 1 - 6/30

So, on Solving we will get 0.8.

HOPE IT HELPS.