11
(IV) x
4, y =
(v) x=-3, y = -6
(vi) x=
From the information given below, find which of the point is
d(Q, R) = 3
If the points are not collinear, state so
(i) d(P, R)= 7,
d(P, Q) = 10,
(ii) d(R.S) = 8,
d(S, T) = 6,
T= ,
(iii) d(A, B)= 16, d(C, A)=9,
(RT) 4
d(B, C) = 7
(iv) d(L, M)= 11,
d(M, N) = 12,
d(N, L) = 8
(v) (X,Y)= 15,
d(Y,Z) = 7,
d(X, Z) = 8
(vi) d(D, E) = 5,
d(E,F)=8,
(D, F)= 6
Answers
Answered by
3
Given : d(Q, R) = 3
d(P, R)= 7,
d(P, Q) = 10
To Find : Points are colinear or not
Solution:
d(Q, R) = 3
d(P, R)= 7,
d(P, Q) = 10,
7 + 3 = 10
PR + RQ = PQ
P -- 7 -- R - 3 - Q
d(R.S) = 8,
d(S, T) = 6
(RT) 4
Not colinear
d(A, B)= 16, d(C, A)=9 d(B, C) = 7
9 + 7 = 16
AC + CB = AB
A 9 C 7 B
d(L, M)= 11,
d(M, N) = 12,
d(N, L) = 8
Not colinear
(X,Y)= 15,
d(Y,Z) = 7,
d(X, Z) = 8
XZ + ZY = XY
8 + 7 = 15
X 8 Z 7 Y
d(D, E) = 5,
d(E,F)=8,
(D, F)= 6
Not colinear
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