Math, asked by gajanankukade819, 6 months ago

11
(IV) x
4, y =
(v) x=-3, y = -6
(vi) x=
From the information given below, find which of the point is
d(Q, R) = 3
If the points are not collinear, state so
(i) d(P, R)= 7,
d(P, Q) = 10,
(ii) d(R.S) = 8,
d(S, T) = 6,
T= ,
(iii) d(A, B)= 16, d(C, A)=9,
(RT) 4
d(B, C) = 7
(iv) d(L, M)= 11,
d(M, N) = 12,
d(N, L) = 8
(v) (X,Y)= 15,
d(Y,Z) = 7,
d(X, Z) = 8
(vi) d(D, E) = 5,
d(E,F)=8,
(D, F)= 6​

Answers

Answered by amitnrw
3

Given : d(Q, R) = 3

d(P, R)= 7,

d(P, Q) = 10

To Find : Points are colinear or not

Solution:

d(Q, R) = 3

d(P, R)= 7,

d(P, Q) = 10,

7 + 3 = 10

PR + RQ  = PQ

P    --    7     --     R    -   3   -    Q  

d(R.S) = 8,

d(S, T) = 6

(RT) 4

Not colinear

d(A, B)= 16, d(C, A)=9 d(B, C) = 7

9 + 7  = 16

AC + CB = AB

A        9         C        7            B

d(L, M)= 11,

d(M, N) = 12,

d(N, L) = 8

Not colinear

(X,Y)= 15,

d(Y,Z) = 7,

d(X, Z) = 8

XZ + ZY  = XY

8 + 7 = 15

X     8        Z       7         Y

d(D, E) = 5,

d(E,F)=8,

(D, F)= 6​

Not colinear

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