11 men can dig 6 3 by 4 m long trends on one day how can men should be employed for digging 27 m long trends of same type on one day
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1)men (m1)=11
Length(l1)=63/4=27/4 m
Days(d1)=1
2)m2=?
l2=27
d2=1
m1*d1/l1= m2d2/l2
(11×1)/(27/4) =(m2*1)/27
(11×27×4)/27=m2
44=m2
m2=44
Therefore 44 men required
Length(l1)=63/4=27/4 m
Days(d1)=1
2)m2=?
l2=27
d2=1
m1*d1/l1= m2d2/l2
(11×1)/(27/4) =(m2*1)/27
(11×27×4)/27=m2
44=m2
m2=44
Therefore 44 men required
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