Question

11. One of the equal sides of an isosceles triangle
is 13 cm and its perimeter is 50 cm. Find the
area of the triangle.
answer is
$60cm {}^{2}$
I have given the answers above the chapter is mensuration area of a Trapezium and a polygon please do in class 8th standard explain the method and solve it. only solve if you know otherwise don't solve thank you .​ don't give me any reply If you are going to write rubbish ​​

Answer 1

Answer:

Equal sides of isosceles triangle = 13 cm

Perimeter of triangle = 50 cm

a + b + c = 50

13 + 13 + c = 50

26 + c = 50

c = 50 - 26

c = 24

Area of the triangle = 60 cm²

PLEASE MARK IT BRAINILIEST

Answer 2

Answer:

60cm²

Step-by-step explanation:

Equal side is 13 cm

==

Perimeter=Sum of two equal side+ Third side

==

==

50=26+Third side

50-26=Third side

24=Third side

==

s=Perimeter/2=>50/2=25cm

==

==

Area=√s(s-a)(s-b)(s-c)

=√25(25-13)(25-13)(25-24)

=√25×12×12×1

=√3600cm⁴

=60cm²