Question

11. p(x)=x2 - 3x + 2, 9(x) = 3x + 1

a) Find p(x) + q(x)

b) If p(x) +q(x) +r(x) =0, find r(x)

c)What number is p(1)+q(1)+r(1) ?​

Answer 1

Answer:

a) x2+3

b) -(x2+3)

c) 0

Step-by-step explanation:

a)

p(x)=x2 - 3x + 2, q(x) = 3x + 1

p(x)+q(x) = x2-3x+2+3x+1 = x2+3

b)

r(x) = -(p(x)+q(x)) = -(x2+3)

c)

p(x) +q(x) +r(x) =0 is always zero no matter any value of x