Question

factorise using factor theorem 2x^3-x^2-7x+6​

Answer 1

Answer:

The factor theorem states that a polynomial f(x) has a factor (x−k) if and only if f(k)=0. If x−1 is a factor, then x=1 is a root.

To verify the root, substitute x=1 in f(x)=0.

f(x)=2x

3

+11x

2

−7x−6

f(1)=2(1)

3

+11(1)

2

−7(1)−6

0=2+11−7−6

0=0

Therefore, the given factor (x−1) is a factor of 2x

3

+11x

2

−7x−6