11. Prove that 3√2 is an irrational number.
Answers
Answered by
4
Answer:
3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.So, it concludes that 3+√2 is irrational.
Answered by
1
hope you understood.
❤️❤️❤️❤️❤️❤️❤️
Attachments:
Similar questions