Math, asked by Youngastronomer324, 9 months ago

11. Prove that 3√2 is an irrational number.

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Answered by Anonymous

4

Answer:

3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.So, it concludes that 3+√2 is irrational.

Answered by hempushpasharma0519

1

hope you understood.

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