Question

11
Show that any number of the form 4", neN can never end with the
digit 0.​

Answer 1

Step-by-step explanation:

click on fig to get answer

Answer 2

Answer:

Step-by-step explanation:

For a digit to end with 0 it should have both 2 and 5 as a factor.

After factorizing 4 you get 4= 2*2

                                            =2^2

Therefore 4^n= 2^2*n

It only has 2 as a factor and 5 is missing.

Hence any number of the form 4^n (where n is any natural number) cannot end with the digit zero.

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