Question

11. Show that (p-1) is a factor of (p10 – 1) and also of (p" – 1)​

Answer 1

Answer:

Let g (p) = p10 -1

and h(p) = p11 -1.

On putting p=1 in Eq. (i), we get

g(1)=110-1= 1-1=0 Hence, p-1 is a factor of g(p).

Again, putting p = 1 in Eq. (ii), we get

h (1) = (1)11 -1 = 1 -1 = 0 Hence, p -1 is a factor of h(p).

Answer 2

Answer:

p-1=0

p=1

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