Question

11. Show that the points A (1,2), B (-1,-16) and C (0, - 7) lie on the
graph of the linear equation y = 9x - 7.​

Answer 1

Answer:

For point A ,

y=9x - 7

2=9(1) - 7

2=9-7

2=2

LHS=RHS

For point B ,

y=9x - 7

-16=9(-1) - 7

-16=-9-7

-16=-16

LHS=RHS

For point C ,

y=9x - 7

-7=9(0) - 7

-7=0-7

-7=-7

LHS=RHS

Hence Proved

Answer 2

Step-by-step explanation:

For A(1,2), we have 2=9(1)−7=9−7=2

For B((−1,−16), we have -16=9(−1)−7=−9−7=−16

For C(0,−7), we have - 7=9(0)−7=0−7=−7

We see that the line y=9x−7 is satisfied by the points A(1,2),B(−1,−16) and C(0,−7).

Therefore, A(1,2),B(−1,−16) and C(0,−7) are solutions of the linear equation y=9x−7 and therefore, lie on the graph of the linear equation y=9x−7.