Question

11) Simplify 6a +2a(4a+3b)-12 ab
12) Find the two consecutive odd numbers whose sum is 56​

Answer 1

Answer:

Step-by-step explanation:

(11) ans= → 6a+(2a)(4a+3b)-12ab

   → 6a+(2a×4a+2a×3b)-12ab

   → 6a+(2×4aa+2×3ab)-12ab

   → 6a+(8a^1+1 +6ab)-12ab

  → 6a+(8a²+6ab)-12ab

 → 6a+8a²+6ab-12ab

 → 6a+8a²-6ab

(12) ans= let one consecutive odd number be x

and let the other consecutive odd number be x+3

given sum of those 2 numbers= 56

i.e

x+x+2=56

2x=56-2

2x=54

x=54/2

x=27

Therefore, one consecutive odd number=x=27

and the other consecutive number= x+2= 27+2= 29

Answer 2

Step-by-step explanation:

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