Question

11. Th
9. The stem-and-leaf diagram represents the distance
covered, in km, by a group of amateur runners
during a training session.
Leaf
3 4 6 9
2 2 2 4 4 58
22
Key: 24 means 24 km
Stem
2
0
1
4
(a) Find
(1) the mean distance,
(ii) the median distance,
(iii) the modal distance,
covered by the runners.
(b) A runner is selected at random. Find the
probability that the distance covered by the
runner is a prime number.
12​

Answer 1

Answer:https://www.gauthmath.com/solution/stem-and-leaf-diagram-represents-the-distance-11-ered-in-km-by-a-group-of-amateu-1185566338

Explanation:https://www.gauthmath.com/solution/stem-and-leaf-diagram-represents-the-distance-11-ered-in-km-by-a-group-of-amateu-1185566338

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Answer 2

Answer: Mean distance= 32.267

              Median distance= 32

              Modal distance= 32

Explanation:

Mean= $\frac{1}{15}$ ( 20×4+30×9+40×2+ 3+4+6+9+0+1+2×3+4×2+5+8+2×2)

         =  $\frac{1}{15}$ × 484

        =32.267

Median distance= 32 {8th of 15}

Modal distance=32 { height frequency}

Therefore,

              Mean distance= 32.267

              Median distance= 32

              Modal distance= 32

#SJP1