Math, asked by pavithrav16122005, 1 month ago

11 th maths வர்க்கமூலம் காண்க
 \sqrt{2.89}

Answers

Answered by deepikamr06
1

Answer:

11 th maths வர்க்கமூலம் காண்க

 \sqrt{2.89}

Step-by-step explanation:

 \sqrt{2.89 = 1.7}

Answered by pulakmath007
0

SOLUTION

TO DETERMINE

The value of

 \displaystyle \sf \:  \sqrt{2.89}

EVALUATION

 \displaystyle \sf \:  \sqrt{2.89}

 \displaystyle \sf  =   \sqrt{ \frac{289}{100} }

 \displaystyle \sf  =   \sqrt{ \frac{17 \times 17}{2 \times 2 \times 5 \times 5} }

 \displaystyle \sf  =   \sqrt{ \frac{ {17}^{2} }{ {2}^{2} \times  {5}^{2}  } }

 \displaystyle \sf  =  \frac{17}{2 \times 5}

 \displaystyle \sf  =  \frac{17}{10}

 \displaystyle \sf  =  1.7

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. If x=√3a+2b + √3a-2b / √3a+2b - √3a-2b

prove that bx²-3ax+b=0

https://brainly.in/question/19664646

2. the order of the surd 7√8

https://brainly.in/question/31962770

Similar questions