Question

If a^2+b^2=41 and ab =4, find the value of a+b

Answer 1

Answer:

7

Step-by-step explanation:

(a+b)^2 = a^2+b^2+2ab

= 41+ 2×4

sqrt(a+b)^2 = sqrt 49

a+b = 7

Answer 2

Answer:

a+b=7

Step-by-step explanation:

Formula (a + b)² = A² + B² + 2AB = 41

AB = 4

41 + 2(4) = 41 +8 = 49

A + B = $\sqrt{49}$ = 7