Question

11. The angles of a hexagon are (2x + 5)º, (3x – 5)°, (x + 40)º, (2x + 20)°, (2x + 25)° and
(2x + 35)°. Find the value of x.​

Answer 1

Answer:

sum of

Internal angles of hexagon

(2n-4) Rt.angle

(2x6-4)x90=8x90 = 720 degree

2x +5+3x-5 +x+40+2x +20 +2x +25

+2x+35=720

12x+120 =720

12x=720-120 = 600

x = 600/12=50 degree. Ans

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Answer 2

Answer:

2x+5°+3x-5°+x+40°+2x+20°+2x+25°+2x+35°=720°(sum of angles of hexagon)

12x+120°=720°

12x=720°-120°

12x=600°

$\: \: \: \: \: \: \: \: \: \: x = \frac{600}{12}$

x=50°

=》2x+5°=2(50°)+5°=100°+5°

=105°

=》3x-5°=3(50°)-5°=150°-5°

=145°

=》x+40°=50°+40°

=90°

=》2x+20°=2(50°)+20°=100°+20°

=120°

=》2x+25°=2(50°)+25°=100°+25°

=125°

=》2x+35°=2(50°)+35°=100°+35°

=135°

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