Question

11. The area of a rectangular plot is 340 sq. m. If its breadth is 17 m, find its length
and the perimeter.​

Answer 1

Step-by-step explanation:

${\rm{\fbox{\pink{Given,}}}}$

• Area = 340m²
• Breadth = 17m

${\rm{\fbox{\blue{To \: find,}}}}$

• Length
• Perimeter

${\Large{\bf{\green{Finding \: length:}}}}$

Area = length × breadth

⇒340 = length × 17

⇒340/17 = length

⇒20 = length

.°. Length of the rectangle = 20m

${\Large{\bf{\orange{Finding \: perimeter:}}}}$

Perimeter = 2(length + breadth)

⇒Perimeter = 2(20m+17m)

⇒Perimeter = 40m + 34m

⇒Perimeter = 74m

.°. Perimeter of the rectangle = 74m

Hence, Length and perimeter of the rectangle is 17m and 74m respectively.

Answer 2

Answer:

$\sf Given\begin {cases}\sf Area\:of\:a\:rectangular\:plot=340cm^2 \\ \sf Breadth=17m\end{cases}$

$\sf To\:find\begin {cases}\sf Length \:and\:the\:perimeter\:of\:the\:rectangular\:plot\end {cases}$

Solution:-

let Length be x

As we know that in a rectangle

$\boxed{\sf Area=Length\times Breadth}$

• Substitute the values

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow 340=x\times 17$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow 17x=340$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow x=\dfrac {340}{17}$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow x=20$

$\\\therefore\sf Length\:of\;the\:rectangular\:plot\:is\:20m.$

______________________________

Again we know that in a rectangle

$\boxed{\sf Perimeter=2 (Length+Breadth)}$

• Substitute the values

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow Perimeter=2 (20+17)$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow Petimeter=2\times 37$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow Perimeter=74m$

$\\\\\therefore\sf Perimeter\:of\:the\:rectangular\:plot\:is\:74m.$