11. The diameter of a road roller of length 120 cm is 84 cm. If it takes 500 complete revolutions
to level a playground, then find cost of levelling it at the cost of 75 paise per square metre.
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Step-by-step explanation:
Surface area of cylindrical roller
= 2.pi.r.h
= 2 ×22/7 ×84×120
= 63,360 cm^2
Now
Total area levelling by roller = roof revolution by roller ×surface area of roller
= 500 × 63360 /10000 m^2
= 31680 m^2
Hence cost of levelling by roller
= 75/100×31680
= 23760
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