Question

11. The electrical resistivity of silver is 1.60 x 10-6Ω m. What will be the resistance of a silver wire of length 10 m and cross-sectional area 2 x 10-3 m2?

Answer 1

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Answer 2

Answer:

R=$0.008{\Omega}$

Step-by-step explanation:

It is given that the electrical resistivity of silver is 1.60 x 10-6Ω m and cross-sectional area $2{\times}10^{-3}m^{2}$.

We know that R=$\frac{{\rho}d}{A}$

=$\frac{(1.60{\times}10^{-6}){\times}10}{2{\times}10^{-3}}$

=$\frac{1.60{\times}10^{-6}{\times}10}{2{\times}10^{-3}}$

=$8{\times}10^{-3}{\Omega}$

=$8{\times}\frac{1}{1000}{\Omega}$

R=$0.008{\Omega}$