11. The perimeter of an isosceles triangle is 42 cm and its base is 1/2 times
each of the equal sides. Find (i) the length of each side of the triangle,
(ii) the area of the triangle, and (iii) the height of the triangle.
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Answer:
side=16.8 ,16.8 , 8.4 (units)
height=16.26 (units)
area= 68.292 (sq units)
Step-by-step explanation:
i)
the length of each side of the triangle
(1/2)x+x+x=42
1/2)x+2x=42
(5/2)x=42
x=42x2÷5 cm
side=16.8 cm
hence, sides are 16.8 cm,16.8cm ,8.4 cm
(iii)
the height of the triangle
base^2+height^2=hypotenuse^2
⇒height^2=16.8^2−4.2^2
∴height=16.26cm
3) Area of the triangle
Area=(1/2)base×height
=68.292 sq units
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