Math, asked by shivamk91465, 7 months ago

11. The perimeter of an isosceles triangle is 42 cm and its base is 1/2 times
each of the equal sides. Find (i) the length of each side of the triangle,
(ii) the area of the triangle, and (iii) the height of the triangle.​

Answers

Answered by pratyush15899
5

Answer:

side=16.8 ,16.8 , 8.4 (units)

height=16.26 (units)

area= 68.292 (sq units)

Step-by-step explanation:

i)

the length of each side of the triangle

(1/2)x+x+x=42

1/2)x+2x=42

(5/2)x=42

x=42x2÷5 cm

side=16.8 cm

hence, sides are 16.8 cm,16.8cm ,8.4 cm

(iii)

the height of the triangle

base^2+height^2=hypotenuse^2

⇒height^2=16.8^2−4.2^2

∴height=16.26cm

3) Area of the triangle

Area=(1/2)base×height

=68.292 sq units

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