Question

11. The position s of a particle moving along a straight line at time t is given by s = atcube + bt to the power 5. Find its velocity
at t = 1 s.​

Answer 1

Explanation:

given that ,

s = at³+bt⁵

t = 1sec

As we know that v = Dx/Dt

v = d/DX(at³+bt⁵)

= a(3t²)+b(5t⁴)

v =3at²+5bt⁴

= 3a(1)²+5b(1)⁴

= 3a+5b m/s....;):)

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